lnx-3[ln(x-5)+ln(x+5)]=0

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Solution for lnx-3[ln(x-5)+ln(x+5)]=0 equation:


Simplifying
lnx + -3[ln(x + -5) + ln(x + 5)] = 0

Reorder the terms:
lnx + -3[ln(-5 + x) + ln(x + 5)] = 0
lnx + -3[(-5 * ln + x * ln) + ln(x + 5)] = 0
lnx + -3[(-5ln + lnx) + ln(x + 5)] = 0

Reorder the terms:
lnx + -3[-5ln + lnx + ln(5 + x)] = 0
lnx + -3[-5ln + lnx + (5 * ln + x * ln)] = 0
lnx + -3[-5ln + lnx + (5ln + lnx)] = 0

Reorder the terms:
lnx + -3[-5ln + 5ln + lnx + lnx] = 0

Combine like terms: -5ln + 5ln = 0
lnx + -3[0 + lnx + lnx] = 0
lnx + -3[lnx + lnx] = 0

Combine like terms: lnx + lnx = 2lnx
lnx + -3[2lnx] = 0

Remove brackets around [2lnx]
lnx + -3 * 2lnx = 0

Multiply -3 * 2
lnx + -6lnx = 0

Combine like terms: lnx + -6lnx = -5lnx
-5lnx = 0

Solving
-5lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '-5'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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